If 3p – q = 6 and 2p + 3q = 4, find q
- A.
o - B.^{1}/_{2}
- C.
2/3 - D.
1 - E.
3^{3}/_{7}
Correct Answer: Option A
Explanation
3p – q = 6 …….. 1
2p + 3q = 4 ……. 2
Multiply eqn 1 by 3
9p – 3q = 18 …….. 3
2p – 3q = 4 ……… 2
Add eqn3 and eqn2
11p = 22 => p = ^{22}/_{11} = 2
Substitute for p =2 in eqn1
3p – q = 6
3×2 – q = 6 => 6 – q = 6 => -q = 6 – 6
q = 0